Optimal. Leaf size=246 \[ -\frac{\sqrt{a+b x} \sqrt{c+d x} \left (-35 a^2 d^2+10 a b c d+b^2 c^2\right )}{8 b^4 d}-\frac{(b c-a d) \left (-35 a^2 d^2+10 a b c d+b^2 c^2\right ) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b} \sqrt{c+d x}}\right )}{8 b^{9/2} d^{3/2}}-\frac{\sqrt{a+b x} (c+d x)^{3/2} \left (-\frac{35 a^2 d}{b}+10 a c+\frac{b c^2}{d}\right )}{12 b^2 (b c-a d)}-\frac{2 a^2 (c+d x)^{5/2}}{b^2 \sqrt{a+b x} (b c-a d)}+\frac{\sqrt{a+b x} (c+d x)^{5/2}}{3 b^2 d} \]
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Rubi [A] time = 0.26803, antiderivative size = 246, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.273, Rules used = {89, 80, 50, 63, 217, 206} \[ -\frac{\sqrt{a+b x} \sqrt{c+d x} \left (-35 a^2 d^2+10 a b c d+b^2 c^2\right )}{8 b^4 d}-\frac{(b c-a d) \left (-35 a^2 d^2+10 a b c d+b^2 c^2\right ) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b} \sqrt{c+d x}}\right )}{8 b^{9/2} d^{3/2}}-\frac{\sqrt{a+b x} (c+d x)^{3/2} \left (-\frac{35 a^2 d}{b}+10 a c+\frac{b c^2}{d}\right )}{12 b^2 (b c-a d)}-\frac{2 a^2 (c+d x)^{5/2}}{b^2 \sqrt{a+b x} (b c-a d)}+\frac{\sqrt{a+b x} (c+d x)^{5/2}}{3 b^2 d} \]
Antiderivative was successfully verified.
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Rule 89
Rule 80
Rule 50
Rule 63
Rule 217
Rule 206
Rubi steps
\begin{align*} \int \frac{x^2 (c+d x)^{3/2}}{(a+b x)^{3/2}} \, dx &=-\frac{2 a^2 (c+d x)^{5/2}}{b^2 (b c-a d) \sqrt{a+b x}}+\frac{2 \int \frac{(c+d x)^{3/2} \left (-\frac{1}{2} a (b c-5 a d)+\frac{1}{2} b (b c-a d) x\right )}{\sqrt{a+b x}} \, dx}{b^2 (b c-a d)}\\ &=-\frac{2 a^2 (c+d x)^{5/2}}{b^2 (b c-a d) \sqrt{a+b x}}+\frac{\sqrt{a+b x} (c+d x)^{5/2}}{3 b^2 d}-\frac{\left (b^2 c^2+10 a b c d-35 a^2 d^2\right ) \int \frac{(c+d x)^{3/2}}{\sqrt{a+b x}} \, dx}{6 b^2 d (b c-a d)}\\ &=-\frac{\left (b^2 c^2+10 a b c d-35 a^2 d^2\right ) \sqrt{a+b x} (c+d x)^{3/2}}{12 b^3 d (b c-a d)}-\frac{2 a^2 (c+d x)^{5/2}}{b^2 (b c-a d) \sqrt{a+b x}}+\frac{\sqrt{a+b x} (c+d x)^{5/2}}{3 b^2 d}-\frac{\left (b^2 c^2+10 a b c d-35 a^2 d^2\right ) \int \frac{\sqrt{c+d x}}{\sqrt{a+b x}} \, dx}{8 b^3 d}\\ &=-\frac{\left (b^2 c^2+10 a b c d-35 a^2 d^2\right ) \sqrt{a+b x} \sqrt{c+d x}}{8 b^4 d}-\frac{\left (b^2 c^2+10 a b c d-35 a^2 d^2\right ) \sqrt{a+b x} (c+d x)^{3/2}}{12 b^3 d (b c-a d)}-\frac{2 a^2 (c+d x)^{5/2}}{b^2 (b c-a d) \sqrt{a+b x}}+\frac{\sqrt{a+b x} (c+d x)^{5/2}}{3 b^2 d}-\frac{\left ((b c-a d) \left (b^2 c^2+10 a b c d-35 a^2 d^2\right )\right ) \int \frac{1}{\sqrt{a+b x} \sqrt{c+d x}} \, dx}{16 b^4 d}\\ &=-\frac{\left (b^2 c^2+10 a b c d-35 a^2 d^2\right ) \sqrt{a+b x} \sqrt{c+d x}}{8 b^4 d}-\frac{\left (b^2 c^2+10 a b c d-35 a^2 d^2\right ) \sqrt{a+b x} (c+d x)^{3/2}}{12 b^3 d (b c-a d)}-\frac{2 a^2 (c+d x)^{5/2}}{b^2 (b c-a d) \sqrt{a+b x}}+\frac{\sqrt{a+b x} (c+d x)^{5/2}}{3 b^2 d}-\frac{\left ((b c-a d) \left (b^2 c^2+10 a b c d-35 a^2 d^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{c-\frac{a d}{b}+\frac{d x^2}{b}}} \, dx,x,\sqrt{a+b x}\right )}{8 b^5 d}\\ &=-\frac{\left (b^2 c^2+10 a b c d-35 a^2 d^2\right ) \sqrt{a+b x} \sqrt{c+d x}}{8 b^4 d}-\frac{\left (b^2 c^2+10 a b c d-35 a^2 d^2\right ) \sqrt{a+b x} (c+d x)^{3/2}}{12 b^3 d (b c-a d)}-\frac{2 a^2 (c+d x)^{5/2}}{b^2 (b c-a d) \sqrt{a+b x}}+\frac{\sqrt{a+b x} (c+d x)^{5/2}}{3 b^2 d}-\frac{\left ((b c-a d) \left (b^2 c^2+10 a b c d-35 a^2 d^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{1-\frac{d x^2}{b}} \, dx,x,\frac{\sqrt{a+b x}}{\sqrt{c+d x}}\right )}{8 b^5 d}\\ &=-\frac{\left (b^2 c^2+10 a b c d-35 a^2 d^2\right ) \sqrt{a+b x} \sqrt{c+d x}}{8 b^4 d}-\frac{\left (b^2 c^2+10 a b c d-35 a^2 d^2\right ) \sqrt{a+b x} (c+d x)^{3/2}}{12 b^3 d (b c-a d)}-\frac{2 a^2 (c+d x)^{5/2}}{b^2 (b c-a d) \sqrt{a+b x}}+\frac{\sqrt{a+b x} (c+d x)^{5/2}}{3 b^2 d}-\frac{(b c-a d) \left (b^2 c^2+10 a b c d-35 a^2 d^2\right ) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b} \sqrt{c+d x}}\right )}{8 b^{9/2} d^{3/2}}\\ \end{align*}
Mathematica [A] time = 0.50918, size = 194, normalized size = 0.79 \[ \frac{\sqrt{c+d x} \left (\frac{\sqrt{d} \left (5 a^2 b d (7 d x-20 c)+105 a^3 d^2+a b^2 \left (3 c^2-38 c d x-14 d^2 x^2\right )+b^3 x \left (3 c^2+14 c d x+8 d^2 x^2\right )\right )}{\sqrt{a+b x}}-\frac{3 \sqrt{b c-a d} \left (-35 a^2 d^2+10 a b c d+b^2 c^2\right ) \sinh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b c-a d}}\right )}{\sqrt{\frac{b (c+d x)}{b c-a d}}}\right )}{24 b^4 d^{3/2}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.022, size = 692, normalized size = 2.8 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 5.60269, size = 1314, normalized size = 5.34 \begin{align*} \left [\frac{3 \,{\left (a b^{3} c^{3} + 9 \, a^{2} b^{2} c^{2} d - 45 \, a^{3} b c d^{2} + 35 \, a^{4} d^{3} +{\left (b^{4} c^{3} + 9 \, a b^{3} c^{2} d - 45 \, a^{2} b^{2} c d^{2} + 35 \, a^{3} b d^{3}\right )} x\right )} \sqrt{b d} \log \left (8 \, b^{2} d^{2} x^{2} + b^{2} c^{2} + 6 \, a b c d + a^{2} d^{2} - 4 \,{\left (2 \, b d x + b c + a d\right )} \sqrt{b d} \sqrt{b x + a} \sqrt{d x + c} + 8 \,{\left (b^{2} c d + a b d^{2}\right )} x\right ) + 4 \,{\left (8 \, b^{4} d^{3} x^{3} + 3 \, a b^{3} c^{2} d - 100 \, a^{2} b^{2} c d^{2} + 105 \, a^{3} b d^{3} + 14 \,{\left (b^{4} c d^{2} - a b^{3} d^{3}\right )} x^{2} +{\left (3 \, b^{4} c^{2} d - 38 \, a b^{3} c d^{2} + 35 \, a^{2} b^{2} d^{3}\right )} x\right )} \sqrt{b x + a} \sqrt{d x + c}}{96 \,{\left (b^{6} d^{2} x + a b^{5} d^{2}\right )}}, \frac{3 \,{\left (a b^{3} c^{3} + 9 \, a^{2} b^{2} c^{2} d - 45 \, a^{3} b c d^{2} + 35 \, a^{4} d^{3} +{\left (b^{4} c^{3} + 9 \, a b^{3} c^{2} d - 45 \, a^{2} b^{2} c d^{2} + 35 \, a^{3} b d^{3}\right )} x\right )} \sqrt{-b d} \arctan \left (\frac{{\left (2 \, b d x + b c + a d\right )} \sqrt{-b d} \sqrt{b x + a} \sqrt{d x + c}}{2 \,{\left (b^{2} d^{2} x^{2} + a b c d +{\left (b^{2} c d + a b d^{2}\right )} x\right )}}\right ) + 2 \,{\left (8 \, b^{4} d^{3} x^{3} + 3 \, a b^{3} c^{2} d - 100 \, a^{2} b^{2} c d^{2} + 105 \, a^{3} b d^{3} + 14 \,{\left (b^{4} c d^{2} - a b^{3} d^{3}\right )} x^{2} +{\left (3 \, b^{4} c^{2} d - 38 \, a b^{3} c d^{2} + 35 \, a^{2} b^{2} d^{3}\right )} x\right )} \sqrt{b x + a} \sqrt{d x + c}}{48 \,{\left (b^{6} d^{2} x + a b^{5} d^{2}\right )}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{2} \left (c + d x\right )^{\frac{3}{2}}}{\left (a + b x\right )^{\frac{3}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.52189, size = 468, normalized size = 1.9 \begin{align*} \frac{1}{24} \, \sqrt{b^{2} c +{\left (b x + a\right )} b d - a b d} \sqrt{b x + a}{\left (2 \,{\left (b x + a\right )}{\left (\frac{4 \,{\left (b x + a\right )} d{\left | b \right |}}{b^{6}} + \frac{7 \, b^{18} c d^{4}{\left | b \right |} - 19 \, a b^{17} d^{5}{\left | b \right |}}{b^{23} d^{4}}\right )} + \frac{3 \,{\left (b^{19} c^{2} d^{3}{\left | b \right |} - 22 \, a b^{18} c d^{4}{\left | b \right |} + 29 \, a^{2} b^{17} d^{5}{\left | b \right |}\right )}}{b^{23} d^{4}}\right )} - \frac{4 \,{\left (\sqrt{b d} a^{2} b^{2} c^{2}{\left | b \right |} - 2 \, \sqrt{b d} a^{3} b c d{\left | b \right |} + \sqrt{b d} a^{4} d^{2}{\left | b \right |}\right )}}{{\left (b^{2} c - a b d -{\left (\sqrt{b d} \sqrt{b x + a} - \sqrt{b^{2} c +{\left (b x + a\right )} b d - a b d}\right )}^{2}\right )} b^{5}} + \frac{{\left (\sqrt{b d} b^{3} c^{3}{\left | b \right |} + 9 \, \sqrt{b d} a b^{2} c^{2} d{\left | b \right |} - 45 \, \sqrt{b d} a^{2} b c d^{2}{\left | b \right |} + 35 \, \sqrt{b d} a^{3} d^{3}{\left | b \right |}\right )} \log \left ({\left (\sqrt{b d} \sqrt{b x + a} - \sqrt{b^{2} c +{\left (b x + a\right )} b d - a b d}\right )}^{2}\right )}{16 \, b^{6} d^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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